很简单的c语言练习求解？
main()
{
int day,month,year,sum,leap;
printf("\nplease input year,month,day\n";
scanf("%d,%d,%d",&year,&month,&day);
switch(month)
{
case 1: sum=0;break;
case 2: sum=31;break;
case 3: sum=59;break;
case 4: sum=90;break;
case 5: sum=120;break;
case 6: sum=151;break;
case 7: sum=181;break;
case 8: sum=212;break;
case 9: sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
}
sum=sum+day;
if(month>12||day>31) printf("You are pig!";
if(year%400==0||(year%4==0&&year%100!=0))
leap=1;
else
leap=0;
if(leap==1&&month>2)
sum++;
printf("It is the %dth day.",sum);}
运行2005，18，45
后会输出You are pig!，可是还是会输出多少天，如何解决，谢谢！
Re:很简单的c语言练习求解？
main()
{
int day,month,year,sum,leap;
printf("\nplease input year,month,day\n";
scanf("%d,%d,%d",&year,&month,&day);
switch(month)
{
case 1: sum=0;break;
case 2: sum=31;break;
case 3: sum=59;break;
case 4: sum=90;break;
case 5: sum=120;break;
case 6: sum=151;break;
case 7: sum=181;break;
case 8: sum=212;break;
case 9: sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
}
sum=sum+day;
if(month>12||day>31) printf("You are pig!";
else {
if(year%400==0||(year%4==0&&year%100!=0))
leap=1;
else
leap=0;
if(leap==1&&month>2)
sum++;
printf("It is the %dth day.",sum);
}
} /* to teminate the main bracket */
;